deletions | additions       diff --git a/mas ch.6.tex b/mas ch.6.tex  index 5c26648..51cbcd0 100644  --- a/mas ch.6.tex  +++ b/mas ch.6.tex 
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step 5\\  we know the z score is 1.5, on the table that corresponds with .9599$\approx96\%$\\ step 6\\  1-.9599=0.0401  step 7\\  Percentage of female college bound seniors who scored 675 or more on the SAT are about $4\%$\\  \subsection{6.24}  $z=\frac{675-530}{100}=1.55. From a z score table we see tat probability is 0.9394.This gives the percentage less than 675 so to find percent greater than just take the compliment, $1-0.9394= 0.0606=6\%$