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\subsection{5.24}  $(593+530/1858=60.4\%$  \subsection{5.25}  Following the guided excersice excersice\  $P(Liberal)=530/1858=28.5\%$\\  $P(Democrat)=689/1858=37.1\%$\\  They arent mutually exclusive because you can see that there are people who are both liberal and democrat.\\  $P(Lib and Dem)=(306)/1858=16.5\%$\\  If we dont subtract away the probability of people being democrat and liberal from that equation, you will be over counting.\\  $P(Lib or Dem)=(530+689-306)/1858=49.1\%$\\  \subsection{5.33}  a)$P(Odd or less than 3)=3/6+2/6-1/6=4/6=66.7\%$\\  b)$P(Odd or less than 2)=3/6+1/6-1/6=50\%$\\  \subsection{5.40}  a)$15/50= 30\%$\\  b)$35/50=70\%$\\  c)30/50=60\%$\\  d)20/50=40\%$\\  e)1 because they are compliments.\\  \subsection{5.44}  a)$1-0.23-0.41=0.36$\\  b)$0.41+0.36=0.77$\\  c)$0.41+0.23=0.64$\\  d)a and c are complementary.16 or more mistakes mean 16 up to 30. 15 or fewer all values from 0 up to 15. If you add these together you get the whole experiment. \\  \subsection{5.47}  a)$306/530=57.7\%$\\  b)$104/593=17.53\$%\\  c)The highest percent is with liberal democrats.\\  \subsection{5.57}  Follow the guided exercise\\