The deflection decreases the distance between the membrane and the flat plate thereby increasing the Casimir force. So this system with positive feedback and has potential to be unstable [7]. If the strip is resistant enough, then the Casimir force can be countered by a restoring membrane forces called N. To be brief, I will just get to the results. For a dimensionless system characteristic contant, \(K_c\), versus \(\sigma_{\frac{L}{2}}\) called the normalized deflection, there are regions of stability and unstability. For smaller values of \(\sigma_{\frac{L}{2}}\), we can get an equilibrium state for the membrane. The smallest value for stable equilibrium, \(\sigma_{\frac{L}{2}}^{min}\), describes a state of minimum potential energy for the membrane strip, subject to Casimir force without any other external forces. The larger value, \(\sigma_{\frac{L}{2}}^{max}\), is the condition for unstability for the membrane. For values greater than \(\sigma_{\frac{L}{2}}^{max}\), the membrane will collapse to the plate. Strip will collapse if \(K_c\) is larger than a critical value of 0.245, so stable equilibrium exists for \(K_c<0.245\)