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\section{Vacuum Hypothesis}  Hutchin suggests that Light comes in two independent and separable forms, an up stimulating(excitation) part and a down stimulating (stimulated emission) component, with the vacuum field being purely a down stimulating form. Then the vacuum field can have the observed quantity of the field strength, but also the additional quality that is down stimulating, unallowed to excite electronic states. Returning to clue 1, stating that blackbody radiation has on average an equal ability to cause an up transition as it does a down transition. This is expressed as $B_{12}=B_{21}$, the cross section for excitation is the same as the stimulated emission coefficient. Due to the presence the zero point energy, the electric dipoles in an ensemble will be in a state of constant flux, spontaneously jostling about in space.These fluctuations generate fluctuating fields, exponential in time, which induce dipoles in nearby particles [5]. With this in mind, we want to decompose blackbody radiation into two components- excitation and stimulating emission. Hutchin suggests to decompose radiation into $e^{+i\omega t}$ for up emission and $e^{-i\omega t}$ for down stimulated emission. The power of these fields splits into half of the power to the real field we measure can measure and half into down the down component equally, as is needed by $B_{12}=B_{21}$. Take a real electromagnetic field in the form of \[ cos(k z-\omega t)=\frac{e^{i(kz-\omega t)}}{2}+\frac{e^{-i(kz-\omega t)}}{2}\] decomposed into its respective down and up stimulating components. Any real electromagnetic field can be divided up into equal power in up stimulating compnent and the down stimulating component. Rewriting Einstein's results: The up stimulating capability is equal to $2B_{12}$ times the power in the up stimulating component and the down stimulating capibility is $2B_{21}$ times the power in the down component, again by $B_{12}=B_{21}$. Applying this to the purely down stimulating vacuum field, the ability of the vacuum field to stimulate emission is \[2B_{21}I_{vac}(\nu)=2B_{21}\frac{4 \pi h \nu^3}{c^2}=\frac{B_{21}8 \pi h \nu^3}{c^2}=A_{21}\] This result suggests spontaneous emission is really stimulated emission from the vacuum field.