deletions | additions       diff --git a/textbf_section_The_Biot_Savart__.tex b/textbf_section_The_Biot_Savart__.tex  index 8045c88..faaef0d 100644  --- a/textbf_section_The_Biot_Savart__.tex  +++ b/textbf_section_The_Biot_Savart__.tex 
...
The contributions to the magnetic field from the loop trace out a circle thus the symmetrical horizontal components of the magnetic field cancel leaving a total field $\vec{B}$ pointing upward. Due to this cancellation we only want to integrate the upward components \textit{d}$B_z$. We can isolate the components using \textit{d}$\vec{B}_z = \textit{d}\vec{B}\cos{\theta}$, which comes from the right triangle in the top of figure \ref{fig2} formed by \textit{d}$\vec{B}$, $\vec{B}$, and the radius of the circle. Thus, integrating only the $\hat{z}$ components of equation \ref{eq1} to obtain the total magnetic field we have:  \begin{equation}\label{eq2}  \int{\vec{B}}=\int{\frac{\mu_0}{4\pi}\frac{\textit{I}\textit{d}\vec{l}\times\hat{\textit{r}}} \vec{B}=\int{\frac{\mu_0}{4\pi}\frac{\textit{I}\textit{d}\vec{l}\times\hat{\textit{r}}}  {\textit{r}^2}\cos{\theta}} \end{equation}