deletions | additions       diff --git a/section_The_Biot_Savart_Law__.tex b/section_The_Biot_Savart_Law__.tex  index a7ba182..1e66fc6 100644  --- a/section_The_Biot_Savart_Law__.tex  +++ b/section_The_Biot_Savart_Law__.tex 
...
\begin{equation}\label{eq1}  \textit{d}\vec{B} = \frac{\mu_0}{4\pi} \frac{\textit{I}\textit{d}\vec{l}\times \hat{\textit{r}}} {\textit{r}^2}  \end{equation}  The contributions to the magnetic field from the loop trace out a circle thus the symmetrical horizontal components of the magnetic field cancel leaving a total field $\vec{B}$ pointing upward. Due to this cancellation we only want to integrate the upward components \textit{d}$B_z$. We can isolate these components using \textit{d}$\vec{B}_z = \textit{d}\vec{B}\cos{\theta}$ \textit{d}\vec{B}\cos{\theta}$, which comes from the right triangle in the top of figure \ref{fig2} formed by \textit{d}$\vec{B}$, $\vec{B}$, and the radius of the circle.  \begin{equation}\label{eq2}  \vec{B}=\int{\textit{d}\vec{B_x}}