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Larson Lovdal edited section_Solving_for_the_e__1.tex
over 8 years ago
Commit id: 81d30b9b1cb573807765b7a88acdebf99f1f5d07
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\end{equation}
Using the numerical values from our experimental set up $\textit{R} = 0.33$ (m) $\textit{N} = 72$ turns and $\mu_0=4\pi\times 10^{-7} (\frac{\text{N}}{\text{A}^2})$ [1] the equation becomes:
\begin{equation}\label{eq8}
\frac{q}{m}\frac{\text{(kg)}}{\text{(C)}}=5.196\times10^{7}\frac{\textit{V}}{\textit{I}^2\textit{r}^2}(\frac{\text({A}^2)\text({m}^2)}{\text({V})}) \frac{q}{m}\frac{\text{(kg)}}{\text{(C)}}=5.196\times10^{7}\frac{\textit{V}}{\textit{I}^2\textit{r}^2}\frac{\text({A}^2)\text({m}^2)}{\text({V})}
\end{equation}