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Larson Lovdal edited section_Solving_for_the_e__1.tex
over 8 years ago
Commit id: 1db4058fc8f456933e3208eeed517eaf0dcfb715
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\end{equation}
Using the numerical values from our experimental set up $\textit{R} = 0.33$ (m) $\textit{N} = 72$ turns and $\mu_0=4\pi\times 10^{-7} (\frac{\text{N}}{\text{A}^2})$ the equation becomes:
\begin{equation}\label{eq8}
\frac{q}{m}=5.196\times10^{7}\frac{\textit{V}}{\textit{I}^2\textit{r}^2} \frac{q}{m}=5.196\times10^{7}\frac{\textit{V}}{\textit{I}^2\textit{r}^2}\frac{text{A^2m}{\text{N}}
\end{equation}