First, we know that velocity is not only
\[\textit {v}_2 = \sqrt{\textit 2gh}\]
but also
\[\textit {v}_2 = \frac{V}{tA}\]
and we know that \(A\) is approximately \(10m^2\) because of the equation:
\[A = \frac {V}{h}\]
Also, be careful of units and make sure to make everything standard. There is an error in my calculations in the end result that screams of unit error, but I cannot find it for the life of me. Anyways,
\[\textit {v}_2 = \frac{V}{10t}\]
and the results are as shown.