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Rosa edited We_start_by_applying_the__.tex
almost 9 years ago
Commit id: 91e193b33d4521e764300107672e3f586e0fdb76
deletions | additions
diff --git a/We_start_by_applying_the__.tex b/We_start_by_applying_the__.tex
index b2d4fe5..ec0e47f 100644
--- a/We_start_by_applying_the__.tex
+++ b/We_start_by_applying_the__.tex
...
\end{multline}
Simplifying
\begin{multline}
I\propto (2\pi)^2
f(\mu_d-\mu) |t_{1}|^2 |t_{2}|^2 \Biggr\{
\int f(\mu_d-\mu)\int [1-f(\epsilon-\mu)] P_{1}(\mu_d-\epsilon)d\epsilon \\
-[1-f(\mu_d-\mu)]\int f(\epsilon-\mu) P_{1}(\epsilon-\mu_d) d\epsilon \Biggr\}
\end{multline}
Remarkably, this integral, and therefore the current $I$ is in general nonzero with an asymmetric environment.