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Rosa edited section_Density_of_states_In__.tex
over 8 years ago
Commit id: d4998e0a51ba4a37d54fceab561983c06b7ee700
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\end{mutline}
Using the fact that $\sin k(N+1)=\sin kN \cos k +\cos kN \sin k$, then the whole expression is simplified to
\begin{multline}
\sin k(N+1) \cos kN \sin k + \sin k N (\sin kN-\cos k\sin k(N+1)) = \sin^ k
\end{mutline}
Therefore the final result reads
\begin{equation}
|c_1|^2 = D^2\frac{\sin^2 q \sin ^2 k}{\sin^k -\frac{V_g}{t}\sin kN \sin k(N+1)}
\end{equation}
Finally the density of states coincides with the one in \cite{Park_2013}. Using the fact that we are using $k$ and $q$ wavevectors in units of $a$, the lattice spacing, we have
\begin{equation}
\rho(E)=\frac{\sin q a\sin^ka}{(\pi a t)(\left (\sin^2(ka)+\frac{eV_g}{t}\sin k(N+1)a \right) \sin kNa}
\end{equation}
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