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Rosa edited untitled.tex
about 8 years ago
Commit id: 73af30263a6d3916d2767a70968de0869a03c42e
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\end{eqnarray}
Now we explicitely write down the expressions for the self-energies
\begin{equation}
\Sigma^>_{0,\alpha\delta}(\epsilon) =
\Sigma^{>,e}_{0,\alpha\delta}(\epsilon)+\Sigma^{>,h}_{0,\alpha\delta}(\epsilon) \Sigma^{<,e}_{0,\alpha\delta}(\epsilon)+\Sigma^{<,h}_{0,\alpha\delta}(\epsilon)
\end{equation}
with
\begin{equation}
\Sigma^{>,e}_{0,\alpha\delta}(\epsilon) \Sigma^{<,e}_{0,\alpha\delta}(\epsilon) = 2 i f(\epsilon-\mu_N)\Gamma_{\alpha\delta}(\epsilon)
\end{equation}
and
\begin{equation}
\Sigma^{>,h}_{0,\alpha\delta}(\epsilon) \Sigma^{<,h}_{0,\alpha\delta}(\epsilon) = 2 i f(\epsilon+\mu_N)\Gamma_{\alpha\delta}(-\epsilon)
= 2i f_h(\epsilon)\Gamma_{\alpha\delta}(-\epsilon)
\end{equation}
On the other hand we have for the retarded and advanced self-energies
\begin{equation}