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Rosa edited untitled.tex
about 8 years ago
Commit id: 4f8e4ce0cc8f848d082556d96f0ec0c0c77953b3
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diff --git a/untitled.tex b/untitled.tex
index 3280181..7af7b98 100644
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...
\end{eqnarray}
We now use the explicit expressions for the self-energies
\begin{eqnarray}
&&M^>(\omega)=\frac{2i e^2}{\hbar^2}\sum_{k\beta,q\gamma,\alpha\delta\nu\mu} \int \frac{d\epsilon}{2\pi}\Biggr\{ [\Sigma^{r,h}_{0,\beta\alpha}(\omega+\epsilon) G^{r}_{\alpha\delta}(\omega+\epsilon)
\Sigma^{h,>}_{\delta\gamma} \Sigma^{h,>}_{0,\delta\gamma} G^{r}_{\gamma\nu}(\epsilon)\Gamma_{\nu\mu}](f_{e}(\epsilon)+f_h(\epsilon)) +
\\
\nonumber
&&[\Sigma^{r,h}_{0,\beta\alpha}(\omega+\epsilon) G^{>}_{\alpha\delta}(\omega+\epsilon)
\Sigma^{h,a}_{\delta\gamma} \Sigma^{h,a}_{0,\delta\gamma} G^{r}_{\gamma\nu}(\epsilon)\Gamma_{\nu\mu}](f_{e}(\epsilon)+f_h(\epsilon))+
\\
\nonumber
&& [\Sigma^{>,h}_{0,\beta\alpha}(\omega+\epsilon) G^{a}_{\alpha\delta}(\omega+\epsilon)
\Sigma^{h,a}_{\delta\gamma} \Sigma^{h,a}_{0,\delta\gamma} G^{r}_{\gamma\nu}(\epsilon)\Gamma_{\nu\mu}](f_{e}(\epsilon)+f_h(\epsilon)) \Biggr\}
\end{eqnarray}
Then we obtain,
\begin{eqnarray}
&&M^>(\omega)=\frac{4 e^2}{\hbar^2}\sum_{k\beta,q\gamma,\alpha\delta\nu\mu} \int \frac{d\epsilon}{2\pi}\Biggr\{ [-i\Gamma_{\beta\alpha}] G^{r}_{\alpha\delta}(\omega+\epsilon) \Gamma_{\delta\gamma} G^{r}_{\gamma\nu}(\epsilon)\Gamma_{\nu\mu}](f_{e}(\epsilon)+f_h(\epsilon))(1-f_h(\omega+\epsilon)) +
\\
\nonumber
&&[\sum_{\theta\tau} [-i\Gamma_{\beta\alpha}] G^{r}_{\alpha\theta}(\omega+\epsilon)\Gamma_{\theta\tau}G^{a}_{\tau\delta}(\omega+\epsilon) [i\Gamma_{\delta\gamma}] G^{r}_{\gamma\nu}(\epsilon)\Gamma_{\nu\mu}](f_{e}(\epsilon)+f_h(\epsilon)) (1-f_{e}(\epsilon+\omega)+1-f_h(\epsilon+\omega)) +
\\
\nonumber
&& [\Gamma_{\beta\alpha}(\omega+\epsilon) G^{a}_{\alpha\delta}(\omega+\epsilon) [i\Gamma_{\delta\gamma}] G^{r}_{\gamma\nu}(\epsilon)\Gamma_{\nu\mu}](f_{e}(\epsilon)+f_h(\epsilon)(1-f_h(\omega+\epsilon))) \Biggr\}
\end{eqnarray}
Then we obtain,