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Rosa edited untitled.tex
about 8 years ago
Commit id: 4313479c643521e6c1a89d578fd04a0d2a71e1bb
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Inserting the expressions for the self-energies we get
\begin{align*}
&N^>(\omega)=(e^2/h)\sum_{k\beta,q\gamma, \nu\mu} \int \frac{d\epsilon}{2\pi}
[G_{\beta\nu}^r(\epsilon) \Sigma_{0,\nu\gamma}^>(\epsilon) G_{\gamma\mu}^r(\omega+\epsilon+)
\Sigma_{0,\mu\beta}^{<,h}(\omega+\epsilon+)]+[G_{\beta\nu}^r(\epsilon) \Sigma_{0,\mu\beta}^{<,h}(\omega+\epsilon)]+[G_{\beta\nu}^r(\epsilon) \Sigma_{0,\nu\gamma}^>(\epsilon) G_{\gamma\mu}^<(\omega+\epsilon) \Sigma_{0,\mu\beta}^{a,h}(\omega+\epsilon)]
\\
&+[G_{\beta\nu}^>(\epsilon) \Sigma_{0,\nu\gamma}^a(\epsilon) G_{\gamma\mu}^r(\omega+\epsilon)\Sigma_{0,\mu\beta}^{<,h}(\omega+\epsilon)]+[G_{\beta\nu}^>(\epsilon) \Sigma_{0,\nu\gamma}^a(\epsilon)
G_{\gamma\mu}^<(\omega+\epsilon+) G_{\gamma\mu}^<(\omega+\epsilon) \Sigma_{0,\mu\beta}^{a,h}(\omega+\epsilon)]
\end{align*}
\begin{align*}
&N^>(\omega)=(4e^2/h)\sum_{k\beta,q\gamma, \nu\mu} \int \frac{d\epsilon}{2\pi} \times \Biggr\{
[G_{\beta\nu}^r(\epsilon) \Gamma_{\nu\gamma}
G_{\gamma\mu}^r(\epsilon+\omega) G_{\gamma\mu}^r(\omega+\epsilon) \Gamma_{\mu\beta} (1-f_e(\epsilon)
f_{h}(\epsilon+\omega)] f_{h}(\omega+\epsilon)] \\
&+\sum_{\lambda\delta}[G_{\beta\nu}^r(\epsilon) \Gamma_{\nu\gamma} G_{\gamma\lambda}^r(\omega+\epsilon)
\Gamma_{\lambda\delta}G^a_{\delta\mu}(\epsilon+\omega)[i\Gamma_{\mu\beta}](1-f_e(\epsilon)(f_{h}(\epsilon+\omega)+f_e(\epsilon+\omega))] \Gamma_{\lambda\delta}G^a_{\delta\mu}(\omega+\epsilon)[i\Gamma_{\mu\beta}](1-f_e(\epsilon)(f_{h}(\epsilon+\omega)+f_e(\omega+\epsilon))] \\
&+\sum_{\lambda\delta} G_{\beta\lambda}^r(\epsilon)\Gamma_{\lambda\delta} G_{\delta\nu}^a(\epsilon)[i\Gamma_{\nu\gamma}] G_{\gamma\mu}^r(\omega+\epsilon)(1-f_{e}(\omega+\epsilon)+1-f_{h}(\omega+\epsilon))f_h(\epsilon)\\
&+\sum_{\lambda\delta\theta\tau}[G_{\beta\lambda}^r(\epsilon)\Gamma_{\lambda\delta} G_{\delta\nu}^a(\epsilon)[i\Gamma_{\nu\gamma}] G_{\gamma\theta}^r(\omega+\epsilon)\Gamma_{\theta\tau}
G_{\tau\mu}^a(\omega+\epsilon)[i\Gamma_{\mu\beta}](1-f_{e}(\epsilon)+1-f_{h}(\epsilon))(f_{e}(\epsilon+\omega)+f_{h}(\epsilon+\omega))] G_{\tau\mu}^a(\omega+\epsilon)[i\Gamma_{\mu\beta}](1-f_{e}(\epsilon)+1-f_{h}(\epsilon))(f_{e}(\omega+\epsilon+)+f_{h}(\epsilon+\omega))] \Biggr\}
\end{align*}
Finally, to obtain $N<(t,t)$ we just change $(1-f)\rightarrow f$, and $f\rightarrow (1-f)$.
\begin{align*}