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Rosa edited untitled.tex
about 8 years ago
Commit id: 18c7919a3bee66d86e415266e9ca4de5f5684a16
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S^{>,1}(\omega)= \frac{4e^2}{\hbar^2}\int_{-\infty}^\infty \frac{d\epsilon}{2\pi} \sum_{\beta\gamma\alpha\delta} [G^r_{\beta \alpha}(\epsilon) \Gamma_{\alpha\delta} G^a_{\delta \gamma}(\epsilon) \Gamma_{\alpha\delta} [F_{eh}+F_{hh}]
\end{eqnarray}
with the total noise as $S=S^A+S^B+S^C$
No we compute the second contribution to the noise from $N(t,t')=(e^2/h)\sum_{k\beta,q\gamma} V_{\beta k} V^*_{\gamma q}G_{\beta q}>(t,t') G^{h,<}_{\gamma k}(t',t)$. These two Green functions read
\begin{eqnarray}
G^>_{\beta q^)(t,t') = \frac{1}{h} \sum_\gamma \int dt_1 [G_{\beta\gamma}^r(t,t_1) V_{\gamma q} g^{>}_{q}(t_1,t')+ G_{\beta\gamma}^>(t,t_1) V_{\gamma q} g^{a}_{q}(t_1,t')
\end{eqnarray}
\begin{eqnarray}
G^{<,h}_{\gamma k^)(t,t') = \frac{-1}{h} \sum_\beta \int dt_1 [G_{\gamma\beta}^r(t',t_1) V_{\beta k} g^{<,h}_{k}(t_1,t)+ G_{\gamma\beta}^<(t',t_1) V_{\beta k} g^{a,h}_{k}(t_1,t)
\end{eqnarray}
In the frequency domain the product of these two functions read:
\begin{eqnarray}
N(\omega)=(e^2/h)\sum_{k\beta,q\gamma} \int \frac{d\epsilon}{2\pi} V_{\beta k} V^*_{\gamma q}G_{\beta q}>(\omega+\epsilob) G^{h,<}_{\gamma k}(\epsilon)
\end{eqnarray}
where
\begin{eqnarray}
G^>_{\beta q^)(\omega+\epsilon) = \sum_\gamma [G_{\beta\gamma}^r(\omega+\epsilon) V_{\gamma q} g^{>}_{q}(\omega+\epsilon)+ G_{\beta\gamma}^>(\omega+\epsilon) V_{\gamma q} g^{a}_{q}(\omega+\epsilon)
\end{eqnarray}
\begin{eqnarray}
G^{<,h}_{\gamma k^)(\omega) = \frac{-1}{h} \sum_\beta \int dt_1 [G_{\gamma\beta}^r(\omega) V_{\beta k} g^{<,h}_{k}(\omega)+ G_{\gamma\beta}^<(\omega) V_{\beta k} g^{a,h}_{k}(\omega)
\end{eqnarray}