Mazdak Farrokhzad edited a) Number of blits.tex  about 10 years ago

Commit id: 547743e3a9bdb9770452bd6d293d8f33abd60416

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Given that:  \begin{equation}  \begin{split}  T(2^n) &= \sum_{i = 0}^{n-1} \left[5 \cdot 4^i\right]\\ 4^i\right]  = 5\sum_{i = 0}^{n-1} \left[4^i\right]  &= 5\frac{1 - 4^n}{1 - 4}  = \frac{5 - 5 * 4^n}{-3}\\