Niclas Alexandersson edited b) Algorithm.tex  almost 10 years ago

Commit id: ed7a1c5963fc434687247d91e8eef70d1453b933

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&= m^22^{n-1}\left(2^n - 1\right)\\  T_{\mathtt{max}}(m, n) &= \sum_{i=1}^{2^{n+1}-1}{\left[\floor{\log_2((2^{m+1}-1)^{i-1})} \cdot \floor{\log_2(2^{m+1}-1)} \right]}\\  &< \sum_{i=1}^{2^{n+1}}{\left[ (m+1)^2(i-1) \right]}\\  &= (m+1)^22^{n}\left(2^{n+1} - 1\right 1\right)  \end{align*}  \end{subequations}