Mazdak Farrokhzad edited Version3.tex  over 10 years ago

Commit id: a9587ee284bf3bd4fce24d5d6542c3533951e716

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\frac{d}{2}\sum_{i=0}^{n-1} i^2 +  \frac{d}{2}(1-2n)\sum_{i=0}^{n-1} i =\\  =  (c+d)\sum_{i=0}^{n-1} (n-i) + \frac{d}{2}n^2(n-1) +  \frac{d}{2}(\frac{n(n-1)(2n-1)}{6} +  \frac{d}{2}(1-2n)\frac{1}{2}n(n-1) =\\  =  \frac{1}{2}( (c+d)(n^2 + n) +  d(n^3 - n^2) +  d(