Carson edited sectionSection_title.tex  over 8 years ago

Commit id: daf22f2d6eac0ae39a3641e348459dbbe48d249f

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\begin{equation}\dot{V}=\frac{dV}{dt}\end{equation}  \\  Once this is done, the equations can be shortened. The best fit candidates are as follows:  \\  \noindent  \makebox[0pt][l]{\emph{Exponential} \begin{equation}  Exponential  Fit Equation}  \makebox[\textwidth][c]{$\dot{V}=\lambda V$}  \\  \\  \noindent  \makebox[0pt][l]{\emph{Power Rule} Equation - \dot{V}=\lambda V  \end{equation}  \begin{equation}  Power Rule / General Exponential  Fit Equation}%  \makebox[\textwidth][c]{$\dot{V}=\lambda V^{a}$}%  \\  \\  \noindent  \makebox[0pt][l]{\emph{Logistic} Equation - \dot{V}=\lambda V^{a})  \end{equation}  \begin{equation}  Logistic  Fit Equation}%  \makebox[\textwidth][c]{$\dot{V}=\lambda V\left ( 1-\frac{V}{K} \right )$}%  \\ Equation - \dot{V}=\lambda V\left(1-\frac{V}{K}\right)  \end{equation}  \begin{equation}  Linear Fit Equation - \dot{V}=\frac{aV}{V+b}  \end{equation}