Carson edited sectionSection_title.tex  almost 9 years ago

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Once this is done, the equations can be shortened. The best fit candidates are as follows:  \begin{table}   \begin{tabular}{ c c }  \emph{Exponential} \noindent  \makebox[0pt][l]{\emph{Exponential}  Fit Equation & $\dot{V}=\lambda V$ Equation}  \makebox[\textwidth][c]{$\dot{V}=\lambda V$}  \\ \emph{Power \\  \noindent  \makebox[0pt][l]{\emph{Power  Rule} Fit Equation & $\dot{V}=\lambda V^{a}$ Equation}%  \makebox[\textwidth][c]{$\dot{V}=\lambda V^{a}$}%  \\  \\ \emph{Logistic} \noindent  \makebox[0pt][l]{\emph{Logistic}  Fit Equation & $\dot{V}=\lambda Equation}%  \makebox[\textwidth][c]{$\dot{V}=\lambda  V\left ( 1-\frac{V}{K} \right )$ )$}%  \\ \emph{Linear} \\  \noindent  \makebox[0pt][l]{\emph{Linear}  Fit Equation & $\dot{V}=\frac{aV}{V+b}$ Equation}%  \makebox[\textwidth][c]{$\dot{V}=\frac{aV}{V+b}$}%  \\  \\ \emph{Surface} \noindent  \makebox[0pt][l]{\emph{Surface}  Fit Equation & $\dot{V}=\frac{aV}{(V+b)^{\frac{1}{3}}}$ Equation}%  \makebox[\textwidth][c]{$\dot{V}=\frac{aV}{(V+b)^{\frac{1}{3}}}$}%  \\ \emph{Gompertz} \\  \noindent  \makebox[0pt][l]{\emph{Gompertz}  Fit Equation & $\dot{V}=aV\ln Equation}%  \makebox[\textwidth][c]{$\dot{V}=aV\ln  \left ( \frac{b}{V+c} \right )$ \\   \emph{Bertalanffy} Fit Equation & $\dot{V}=aV^{\frac{2}{3}}-bV$ )$}%  \\&  \\ \end{tabular}   \end{table} \noindent  \makebox[0pt][l]{\emph{Bertalanffy} Fit Equation}%  \makebox[\textwidth][c]{$\dot{V}=aV^{\frac{2}{3}}-bV$}%  \subsection{Data Selection}  \subsection{Fitting Procedure}