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Carson edited sectionSection_title.tex
almost 9 years ago
Commit id: 0febfbe89c1da1843978c2678b42ed0dc74ba0c4
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Once this is done, the equations can be shortened. The best fit candidates are as follows:
\makebox[0pt][1]{\emph{Exponential} Fit Equation}
\makebox[\textwidth][c]{$\dot{V}=\lambda V$} \begin{table}
\begin{tabular}{ c c }
\\
\emph{Exponential} Fit Equation & $\dot{V}=\lambda V$ \\
\noindent
\makebox[0pt][l]{\emph{Power \emph{Power Rule} Fit
Equation}%
\makebox[\textwidth][c]{$\dot{V}=\lambda V^{a}$}%
\\ Equation & $\dot{V}=\lambda V^{a}$ \\
\noindent
\makebox[0pt][l]{\emph{Logistic} \emph{Logistic} Fit
Equation}%
\makebox[\textwidth][c]{$\dot{V}=\lambda Equation & $\dot{V}=\lambda V\left ( 1-\frac{V}{K} \right
)$}% )$ \\
\\
\noindent
\makebox[0pt][l]{\emph{Linear} \emph{Linear} Fit
Equation}%
\makebox[\textwidth][c]{$\dot{V}=\frac{aV}{V+b}$}%
\\ Equation & $\dot{V}=\frac{aV}{V+b}$ \\
\noindent
\makebox[0pt][l]{\emph{Surface} \emph{Surface} Fit
Equation}%
\makebox[\textwidth][c]{$\dot{V}=\frac{aV}{(V+b)^{\frac{1}{3}}}$}% Equation & $\dot{V}=\frac{aV}{(V+b)^{\frac{1}{3}}}$ \\
\\
\noindent
\makebox[0pt][l]{\emph{Gompertz} \emph{Gompertz} Fit
Equation}%
\makebox[\textwidth][c]{$\dot{V}=aV\ln Equation & $\dot{V}=aV\ln \left ( \frac{b}{V+c} \right
)$}%
\\ )$ \\
\noindent
\makebox[0pt][l]{\emph{Bertalanffy} \emph{Bertalanffy} Fit
Equation}%
\makebox[\textwidth][c]{$\dot{V}=aV^{\frac{2}{3}}-bV$}% Equation & $\dot{V}=aV^{\frac{2}{3}}-bV$ \\
& \\
\end{tabular}
\end{table}
\subsection{Data Selection}
\subsection{Fitting Procedure}
...