Pol Grasland-Mongrain edited When_a_laser_beam_of__1.tex  over 8 years ago

Commit id: 3f659356a79685c24b2c34d2d678a821433f4075

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The thermal diffusion path, equal to $\sqrt{4\kappa t}$, with $t$ the laser emission duration, is equal to 0.1 $\mu$m. As $\gamma^{-1} \gg \sqrt{4\kappa t}$, propagation of heat is negligible during laser emission, and term $k \nabla ^2 T$ can be neglected in equation \ref{eq:eqChaleur}. Combination with equation \ref{eq:opticalIntensity} and integration over time lead then to a temperature $T$ at the end of the laser emission:  \begin{equation}  T = T_0 + \frac{\gamma}{S \rho C}E C} aE  \exp(-\gamma r) \ref{eq:eqTemperature}  \end{equation}