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Pol Grasland-Mongrain edited When_a_laser_beam_of__1.tex
over 8 years ago
Commit id: 3f659356a79685c24b2c34d2d678a821433f4075
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The thermal diffusion path, equal to $\sqrt{4\kappa t}$, with $t$ the laser emission duration, is equal to 0.1 $\mu$m. As $\gamma^{-1} \gg \sqrt{4\kappa t}$, propagation of heat is negligible during laser emission, and term $k \nabla ^2 T$ can be neglected in equation \ref{eq:eqChaleur}. Combination with equation \ref{eq:opticalIntensity} and integration over time lead then to a temperature $T$ at the end of the laser emission:
\begin{equation}
T = T_0 + \frac{\gamma}{S \rho
C}E C} aE \exp(-\gamma r)
\ref{eq:eqTemperature}
\end{equation}
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