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ZoƩ Christoff edited This_example_shows_that_direction__.tex
almost 8 years ago
Commit id: 4c4a8e883e0c3b352ca1b080f4a5b8e11e305318
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diff --git a/This_example_shows_that_direction__.tex b/This_example_shows_that_direction__.tex
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\item if $k=n$: Assume that it holds for $k=n-1$: Assume that for agent j at distance n-1 from agent l, j's opinion on (p) stabilizes, that is, for some $m \in \mathbb{N}$, $O^m_ j(p)$ is stable.We need to consider three cases:
\begin{itemize}
\item if there is no inconsistency (between influencers of i's opinion and the given constraints), then O^{m+1}_i(p)=O^m_j(p), and i's opinion on p is stable at stage m+1.
\item if there is some inconsistency, but
O^{m}_i(p)=O^m_j(p), $O^{m}_i(p)=O^m_j(p)$, then
i's $i$'s opinion on
p $p$ is stable at stage
m. $m$.
\item if there is some inconsistency, but
O^{m}_i(p) $O^{m}_i(p) \neq
O^m_j(p), O^m_j(p)$, then
O^{m+1}_j(p) $O^{m+1}_j(p) =
O^{m}_j(p) O^{m}_j(p)$ :
i $i$ does not change his opinion but nothing guarantees that this won't change later on (that's the interesting case). Consider the two possible subcases:
\begin{itemize}
\item a) If consistency occurs at a later stage (say stage
m+t $m+t$ for some
t), $t$), then
O^{m+t+1}_i(p) $O^{m+t+1}_i(p) =
O^{m}_j(p), O^{m}_j(p)$, and
i's $i$'s opinion is stable at stage
m+t+1, $m+t+1$, and
\item b) If consistency never occurs, then
i's $i$'s opinion on
p $p$ is stable already at stage
m. $m$.
\end{itemize}
\end{itemize}
\end{itemize}