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Paul Dennis edited untitled.tex
over 8 years ago
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\[t = \frac{{\pi \cdot \left( {3.3 \times {{10}^{ - 4}} \cdot V - 0.5} \right)^2}}{{1 \times {{10}^{ - 6}}}}\]
Table 2 lists values of t for different values of V. The values of V were chosen corresponding to the volumes of fluid expelled
accompanying from a 1000m thick sediment sequence with changes in
the porosity of
a 350m thick unit of shale of 0.1, 1 and 10\% on dewatering. The corresponding values of t are 2.13, 213 and 2130000 years respectively.