Pablo gallegos edited untitled.tex  almost 9 years ago

Commit id: 3dd4ec7e9efe1eeb57eb396abd480810c251ae34

deletions | additions      

       

\textit{Oh, an empty article!}   Linearización  \begin{eqnarray}   \frac{dh_1}{dt}&=-\sqrt{2g}\frac{a_1}{A_1}\frac{\Delta \frac{d\Delta h_1}{dt}&=-\sqrt{2g}\frac{a_1}{A_1}\frac{\Delta  h_1}{2\sqrt{h_{1,0}}}+ \frac{\Delta u_1}{A_1} \\ \frac{dh_2}{dt}&=\sqrt{2g}\frac{a_1}{A_2}\frac{\Delta h_1}{2\sqrt{h_{1,0}}} -\sqrt{2g}\frac{a_2}{A_2}\frac{\Delta h_2}{2\sqrt{h_{2,0}}} \\  \frac{dh_3}{dt}&=\sqrt{2g}\frac{a_2}{A_3}\frac{\Delta \frac{d h_3}{dt}&=\sqrt{2g}\frac{a_2}{A_3}\frac{\Delta  h_2}{2\sqrt{h_{2,0}}} -\sqrt{2g}\frac{a_3}{A_3}\frac{\Delta h_3}{2\sqrt{h_{3,0}}}+\frac{\Delta u_2}{A_3}\\ \frac{dh_4}{dt}&=\sqrt{2g}\frac{a_3}{A_4}\frac{\Delta \frac{d\Delta h_4}{dt}&=\sqrt{2g}\frac{a_3}{A_4}\frac{\Delta  h_3}{2\sqrt{h_{3,0}}} -\sqrt{2g}\frac{a_4}{A_4}\frac{\Delta h_4}{2\sqrt{h_{4,0}}} \end{eqnarray}   Funciones de transferencia  \begin{eqnarray}