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Know this if we sum over all the log(n) levels we get:  $T(n) = \sum_{j=0}^{log(n-1)} 5^j[(n/5^j)/(log(n/5^j))]$ 5^{j[(\frac{n}{5^j})/(log(\frac{n}{5^j}))]}$  $T(n) = \sum_{j=0}^{log(n-1)} n/log(n-j)$