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Jeremy Ting edited p8.tex
about 10 years ago
Commit id: caa0554476fb10c8d15ce0ea47580da94b4d339b
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index 2db6f3c..e7d76c6 100644
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Using Bezout's identity we know $y(y^{-1}modx) + x(x^{-1}mody)=1$
THEN YOU CAN MULTIPLY BOTH SIDES BY Q. Then you can multiply both sides by $q$.
$qy(y^{-1}modx) + qx(x^{-1}mody)=q$