deletions | additions       diff --git a/2.tex b/2.tex  index 3c9fdd4..f131492 100644  --- a/2.tex  +++ b/2.tex 
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\end{align}  Where $K_1$ and $K_2$ are the equilibrium constants for the first and second step of Reaction (1), respectively. Substituting Eqns (16) and (17) into (15) and rearranging yields the following relationship:  \begin{align}  $[B]_e &= \frac{k_1k_{-2}A_0}{k_1k_2+k_{-1}k_{-2}+k_1k_{-2}} [B][B]_e =\frac{k_1k_{-2}A_0}{k_1k_2+k_{-1}k_{-2}+k_1k_{-2}}  \end{align}  Then, in solving for Eqn (2) at equilibrium,  \begin{align}