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Rounding up to the next but one power of 2, we find that the maximum FFT size that must be supported by the instrument is $2^{27}$ point (134 Mpt). Figure \ref{fig:max_flops} shows how FFT sizes translate to FLOPS for each 10 MHz channel received by the PST instrument. Counterintuitively, despite the reduced FLOPS per 10 MHz channel, the total computational cost for dedispersion increases as we move to higher frequencies. This is purely due to the larger absolute bandwidths of the higher frequency bands of SKA1 meaning more data that needs to be processed per unit time. For example band 5 will have 250 10-MHz frequency channels, while band 1 will have only 70, 10-MHz frequency channels.