deletions | additions       diff --git a/considerations.tex b/considerations.tex  index b5e89ae..102f1b9 100644  --- a/considerations.tex  +++ b/considerations.tex 
...
\begin{equation}  \delta t = 4.15 \times 10^3 \left( \frac{1}{\nu^2} - \frac{1}{(\nu+\delta\nu)^2} \right) {\rm DM},  \end{equation}  where $\delta\nu$ is the channel width and $\nu$ is the frequency of the bottom of the channel. By describing $\delta\nu$ in terms of its reciprocal time resolution $t_{\rm res}$, res}=1/\delta\nu$,  we can determine the DM at which $t_{\rm res} = \delta t$. Using this, we can determine the DM at which the dispersive smearing in a channel is equal to that channels time resolution. This leads to the following requirements: \begin{itemize}