Demian Arancibia edited untitled.tex  almost 9 years ago

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\subsubsection{Cost of Antennas Construction}  According to \cite{moran}, a commonly used rule of thumb for the cost of an antenna is that it is proportional to $D^{\alpha}$, where $\alpha \approx 2.7$ for values of $D$ from a few meters to tens of meters. For $N$ antennas of diameter $D$ meters with accuracy $\frac{\lambda}{16}$, where $\lambda$ is in millimeters we could use \cite{mmadesign} as an upper limit for Antenna construction cost.  \begin{equation}\label{eq:antenna_cost}  \text{Antenna Cost} = \frac{890N(\frac{D}{10})^{2.7}}{(\lambda^{0.7})} + 500(K\$)  \end{equation}  in K\$.  \subsubsection{Cost of Front-end system}  For $M$ frequency bands, each 30\% wide, and dual polarization we could use \cite{mmadesign} as an upper limit for Front-End System Cost:  \begin{equation}\label{eq:fe_cost}  \text{Front-End System Cost} = 45MN + 200M(K\$)  \end{equation}  in K\$.  \subsubsection{Cost of LO system}  We could use \cite{mmadesign} as an upper limit for LO System Cost:  \begin{equation}\label{eq:lo_cost}  \text{LO System Cost} = 80N+100 (K\$) in K\$.  \end{equation}  \subsubsection{IF Transmission Cost}  Introducing $B$ as average baseline, we could use \cite{mmadesign} as an upper limit for IF Transmission Cost:  \begin{equation}\label{eq:IF_Tx_cost}  \text{IF Transmission Cost} = 8BN + 30N + 400(K\$)  \end{equation}  in K\$.  \subsubsection{Correlator Cost}  We could use \cite{mmadesign} Correlator Cost as an upper limit:  \begin{equation}\label{eq:correlator}  \text{Correlator cost} = 2N^2 + 112N +1360(K\$)  \end{equation}  in K\$.  \subsubsection{Cost of Re-configuration Systems Construction}  \section{Data for visual analytics - Python Implementation}\label{sec:python}  This section presents a python code that produces data in the right format for performing visual analytics, consistent with variables in \S~\ref{sec:var} and objectives in \S~\ref{sec:obj}.