this is for holding javascript data
Demian Arancibia edited untitled.tex
almost 9 years ago
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\subsubsection{Cost of Antennas Construction}
According to \cite{moran}, a commonly used rule of thumb for the cost of an antenna is that it is proportional to $D^{\alpha}$, where $\alpha \approx 2.7$ for values of $D$ from a few meters to tens of meters. For $N$ antennas of diameter $D$ meters with accuracy $\frac{\lambda}{16}$, where $\lambda$ is in millimeters we could use \cite{mmadesign} as an upper limit for Antenna construction cost.
\begin{equation}\label{eq:antenna_cost}
\text{Antenna Cost} = \frac{890N(\frac{D}{10})^{2.7}}{(\lambda^{0.7})} + 500
(K\$)
\end{equation}
\subsubsection{Cost of Front-end system}
For $M$ frequency bands, each 30\% wide, and dual polarization we could use \cite{mmadesign} as an upper limit for Front-End System Cost:
\begin{equation}\label{eq:fe_cost}
\text{Front-End System Cost} = 45MN + 200M
(K\$)
\end{equation}
\subsubsection{Cost of LO system}
We could use \cite{mmadesign} as an upper limit for LO System Cost:
\begin{equation}\label{eq:lo_cost}
\text{LO System Cost}
(K\$) = 80N+100
(K\$)
\end{equation}
\subsubsection{IF Transmission Cost}
Introducing $B$ as average baseline, we could use \cite{mmadesign} as an upper limit for IF Transmission Cost:
\begin{equation}\label{eq:IF_Tx_cost}
\text{IF Transmission Cost} = 8BN + 30N + 400
(K\$)
\end{equation}
\subsubsection{Correlator Cost}
We could use \cite{mmadesign} Correlator Cost as an upper limit:
\begin{equation}\label{eq:correlator}
\text{Correlator cost} = 2N^2 + 112N +1360
(K\$)
\end{equation}
\subsubsection{Cost of Re-configuration Systems Construction}
\section{Data for visual analytics - Python Implementation}\label{sec:python}
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