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Demian Arancibia edited untitled.tex
almost 9 years ago
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We will use the geographic latitudes and longitudes to establish pad location in this document. We will calculate the length of the possible baselines using pad positions. We will also calculate length and complexity of the roads, fiber and power networks needed using pad positions. We will use $B$ as the maximum array element separation in any single configuration.
\subsection{Receiver Aspects}
\subsubsection{Bandwidth}
We will use
$R$ $M$ as the number of frequency bands, being
$R_i$ $M_i$ the different frequency bands. If the array bandwidth covered by all
$R_i$ $M_i$ together is $f_{max} - f_{min}$, it is useful for our analysis to use wavelength $\lambda = \frac{c}{f_{max}} = \lambda_{min}$ in [$mm$].
\subsubsection{Temperature}
\subsubsection{Efficiency}
\subsection{Correlator Aspects}
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\subsubsection{Re-configuration Systems Operation Cost}
\subsection{Up-front Costs}
\subsubsection{Cost of Antennas Construction}
According to \cite{moran}, a commonly used rule of thumb for the cost of an antenna is that it is proportional to $D^{\alpha}$, where $\alpha \approx 2.7$ for values of $D$ from a few meters to tens of meters. For
$N$ antennas
of diameter $D$ meters with accuracy $\frac{\lambda}{16}$,
where $\lambda$ is in millimeters we could use \cite{mmadesign} as an upper limit for Antenna construction cost.
\begin{equation}\label{eq:antenna_cost}
\text{Antenna Cost} = \frac{890N(\frac{D}{10})^{2.7}}{(\lambda^{0.7})} + 500
\end{equation}
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