Agustín Valverde Ramos edited Soluci_n_begin_aligned_cos__.tex  over 8 years ago

Commit id: 47ce339e98109f081297349a053472aeb06958c6

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+\mathrm{i}\sin^5\theta) = \\  & = \cos^5 \theta−10\cos^3 \theta\sin^2 \theta+5\cos \theta\sin^4 \theta = \\  & = \cos^5 \theta−10\cos^3 \theta(1-\cos^2\theta)+5\cos \theta(1-\cos^2\theta)^2 = \\  & = \cos^5 \theta−10\cos^3 \theta-10\cos^5\theta+5\cos \theta(1-2\cos^2\theta+4\cos^4\theta) = \\  \end{aligned}  \]