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Alfredo A. Correa edited In_order_to_interpret_the__.tex
over 8 years ago
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In order to interpret the results we calculated the linear response stopping $S_\text{L}(n, v)$ \cite{Lindhard_1964} based on the Linhard RPA dielectric function $\epsilon_\text{RPA}$ for different effective densities $n$ \cite{Giuliani_2005}.
\begin{equation}
S_\text{L}(n, v) = \frac{2 e^2}{\pi v^2} \int_0^\infty
\mathrm{d}k k^{-1} \frac{\mathrm{d}k}{k} \int_0^{k v} \mathrm{d}\omega\omega \Im
1/\varepsilon_\text{RPA}(n, \frac{1}{\varepsilon_\text{RPA}(n, k,
\omega) \omega)}
\end{equation}
(which assumes a proton effective charge of $Z_1 = 1$).
As shown in Fig.~\ref{fig:log_stopping_power}, for $v < 0.1~\mathrm{a.u.}$ the results mimics the response of an electron gas with one electron per $\mathrm{Cu}$ atom.