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Alfredo A. Correa edited figures/energy_dis7/caption.tex
almost 8 years ago
Commit id: 07d34732d859b848cf7202602db81065c3c4fa66
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\label{fig:fit_graph} (color online). The increase of $E$ as a function of proton position at
velocities $v = 0.06 ~\mathrm{a.u.}$ (green dashed line) along $\langle 100\rangle$ channeling trajectory and the adiabatic energy (magenta dot-dashed line).
The adiabatic curve would correspond to a proton moving infinitely
slowly $v=0$), slowly, where there is no transfer of energy, just oscillations of the total energy with
a an overall zero slope.
%The initial (ground state energy) is subtracted.
The oscillations in the curves reflect the periodicity of the $\mathrm{Cu}$ lattice.
The red solid line shows the energy difference (subtraction of adiabatic energy from the $v = 0.06 ~\mathrm{a.u.}$ curves).
...
%%should be added a constant value of $-16856.62389 ~\mathrm{a.u.}$.%
A linear fit , $y = a + bx$ (blue line) yields a slope of $6.989 \times 10^{-3}~E_\text{h}/a_0$ with an error of $\pm 6.936 \times 10^{-5}~E_\text{h}/a_0$.
We then proceed for a linear fit in addition to an oscillatory function $y = a + bx + A\cos(k x + \phi)$ (black dotted line) to capture any remnant oscillation.
This oscillatory fit generates a slope of $7.435 \times 10^{-3}~E_\text{h}/a_0$ with an error of $\pm 8.52 \times 10^{-7}~E_\text{h}/a_0$, that is a minimal fitting error
in is obtained in the \emph{channeling} trajectory.