Namgyun Lee edited untitled.tex  about 8 years ago

Commit id: 789896171dc5a37347b58c775846c699bbe5f5f5

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Therefore, it follows that   \begin{eqnarray}  Df(x) &=& \left[ \frac{\partial \|x\|_{\ell_2}^2}{\partial x_1}, \dots, \frac{\partial \|x\|_{\ell_2}^2}{\partial x_n} \right] \nonumber\\  &=& \left[2x_1, \ldots, 2x_n \right] \nonumber\\  &=& 2x. \nonumber  \end{eqnarray}