Jan Jensen edited Delta_sigma_i__H_alpha__.tex  almost 9 years ago

Commit id: 2a3441b0272a10527699b44afdaf633a1c08066d

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\label{eqn:sigmahab}  \Delta \sigma^i_{H\alpha B}=\Delta\sigma^i_{1^\circ H\alpha B}(r_{\mathrm{H\alpha O}},\theta_{\mathrm{H\alpha}},\rho_{\mathrm{H\alpha}})+\Delta\sigma^i_{2^\circ H\alpha B}(r_{\mathrm{OH\alpha}},\theta_{\mathrm{O}},\rho_{\mathrm{O}})$$  \end{equation}  $\Delta\sigma^i_{1^\circ H \alphaB}$ \alpha B}$  is computed using the structural models shown in Figure \ref{fig:HAB} as the change in chemical shielding of the backbone and C$\beta$ atoms in Ac-A-NMe relative that of the free monomer computed at the OPBE/6-31G(d,p)//PM6 level of theory for a variety of orientations (see subsection \ref{subsec:HBscan} for more information) while the internal monomer geometries are kept fixed. $\Delta\sigma^i_{2^\circ HB}$ is computed as the change in the chemical shielding of the top amide group in Figure \ref{fig:HAB}a. For H$\alpha$ the chemical shielding is taken as the average of the three hydrogen atom on the methyl group of the acetamide. Note in this case that the amide nitrogen and hydrogen formally belong to residue $i+1$ and that $r_\mathrm{HO}$, $\theta$, and $\rho$ are defined relative to the carbonyl oxygen of residue $i$ rather than the amide proton as for $\Delta\sigma^i_{1^\circ HB}$. $r_\mathrm{H\alpha O}$, $\theta$, and $\rho$ are therefore labeled $r_\mathrm{OH\alpha}$, $\theta_{\mathrm{O}}$, and $\rho_{\mathrm{O}}$ in Eq \ref{eqn:sigmahab}.