Xavier Holt edited begin_claim_The_algorithm_runs__.tex  about 8 years ago

Commit id: 4687a9471a721f98de4da6adbd6bb7d835c20200

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&=2\left(2R(n/4) + O(\log n/2) + O(n/2)\right) + O(\log n) + O(n)\\  &= iO(n) + \sum_{j=0}^{i-1} 2^j O(\log \frac{n}{2^i}) + 2^iR(\frac{n}{2^i})\\  &= O(n\log n) + \sum_{j=0}^{\log n-1} 2^j O(\log \frac{n}{2^i}) + 2^{\log n}R(1)\\  &= O(n\log n) + n^{\log 2}O(1) + \sum_{j=0}^{\log n-1} 2^j (\log n - \log{2^j}) \\ \log{2^j})\\  &= O(n\log n) + O(n) + \left(\log n\sum_{j=0}^{\log n-1} 2^j - \sum_{j=0}^{\log n-1} 2^j\log{2^j} \right)\\   &= O(n\log n) + \left(\log n \times 2^{\log n} - C \right) &\text{with $C\geq0$}\\  &= O(n\log n) + \left(n\log n - C \right) &\text{inner bracket $\geq 0$} \\ 0$}\\  \end{align*}  \end{proof}