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Matteo Cantiello edited Convective Velocities.tex
over 9 years ago
Commit id: ac9c06b2c2903fb0b4121127d1d8f6d716502317
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...
\begin{equation}\label{eq:velocity2}
\bar{v}^2 = - \frac{1}{8} g (\Delta \rho (\lambda)/\rho) \lambda.
\end{equation}
Relating $\Delta \rho$ and $\Delta T$ requires the equation of state for the gas $\rho = \rho (\mu, T,
\P)$, \p)$, which in differential form can be written as
\begin{equation}
\D\rho = \bigg(\frac{\partial \rho}{\partial \mu} \bigg)_{\p,T} \D\mu + \bigg(\frac{\partial \rho}{\partial T} \bigg)_{\p,\mu} \D T + \bigg(\frac{\partial \rho}{\partial \p} \bigg)_{\mu,T} \D\p,
\end{equation}
,
\begin{equation}
\D\rho = \frac{\rho}{\mu}\bigg(\frac{\partial \ln \rho}{\partial \ln \mu} \bigg)_{\p,T} \D\mu + \frac{\rho}{T} \bigg(\frac{\partial \ln \rho}{\partial \ln T} \bigg)_{\p,\mu} \D T + \frac{\rho}{\p} \bigg(\frac{\partial \ln \rho}{\partial \ln \p} \bigg)_{\mu,T} \D\p
\end{equation}
and finally
\begin{equation}
...
\begin{equation}
Q = \frac{4-3 \beta}{\beta} - \bigg(\frac{\partial \ln \mu}{\partial \ln T} \bigg)_{\p},
\end{equation}
with $\beta =
\P_{Gas}/\P$. \p_{Gas}/\p$. Plugging Eq.~\ref{eq:deltarho} in \ref{eq:velocity2} one obtains
\begin{equation}
\bar{v}^2 = \frac{1}{8} g Q (\Delta T (\lambda) / T) \lambda .
\end{equation}