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Matteo Cantiello edited Convective Efficiency.tex
over 9 years ago
Commit id: 7eded1367df9e53d3dc6fde3c8267d937f741b80
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\end{equation}
with $\Delta T $ the temperature difference between the center of the turbulent element and the surrounding matter averaged over its lifetime. Given the area $A$ of the element and its lifetime $\lambda/\bar{v}$ the total radiated energy is
\begin{equation}
E_{rad} =
-\frac{4ac}{3}\frac{T^3}{\kappa \frac{4ac}{3}\frac{T^3}{\kappa \rho}\frac{\Delta T}{\lambda/2} \frac{\lambda A}{\bar{v}}.
\end{equation}
The energy excess content carried by the convective element before dissolving is $\cp \rho \Delta T^{*} V$ with $\Delta T^{*}$ here being the temperature excess of the element over its surroundings at the end of its path. Obviously $\Delta T^{*} \simeq \Delta T$, and in the classic Bohm-Vitense work the choice $\Delta T^{*} = 2 \Delta T$ is made.
Using these quantities one can define a convective efficiency $\Gamma$ as
\begin{equation}\label{eq:gamma}
\Gamma = \frac{2 \cp \rho \Delta T V}{\frac{4ac}{3}\frac{T^3}{\kappa \rho}\frac{\Delta T}{\lambda/2} \frac{\lambda A}{\bar{v}}}
\end{equation}