deletions | additions       diff --git a/Convective Efficiency.tex b/Convective Efficiency.tex  index 34686b2..cfe93ca 100644  --- a/Convective Efficiency.tex  +++ b/Convective Efficiency.tex 
...
\begin{equation}  E_{rad} = -\frac{4ac}{3}\frac{T^3}{\kappa \rho}\frac{\Delta T}{\lambda/2} \frac{\lambda A}{\bar{v}}.   \end{equation}  The energy excess content carried by the convective element before dissolving is $\cp \rho \Delta T^{*} V$ with $\Delta T^{*}$ here being the temperature excess of the element over its surroundings at the end of its path. Obviously $\Delta T^{*} \simeq \Delta T$, and in the classic B\{"}ohm-Vitense Bohm-Vitense  work the choice $\Delta T^{*} = 2 \Delta T$ is made.