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Stefano Maffezzoli Felis edited Energies.tex
over 8 years ago
Commit id: f15d9d4b6477f5aea9594f9cba93505c393e20fc
deletions | additions
diff --git a/Energies.tex b/Energies.tex
index f921e3f..7178564 100644
--- a/Energies.tex
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Each block can be easily diagonalized and one gets eigentates and eigenenergies of the total Hamiltonian
\begin{equation}
\begin{align}
&E^{1/2}_N=\epsilon_N\mp
\sqrt{(2\hbar\frac{\Gamma_1\Gamma_2}{\omega_0^2})^2+(\epislon_2\; e^{-2\Gamma_2^2}L_N(4\Gamma_2^2)-\epislon_1\; \sqrt{(2\hbar\frac{\Gamma_1\Gamma_2}{\omega_0^2})^2+(\epsilon_2\; e^{-2\Gamma_2^2}L_N(4\Gamma_2^2)-\epsilon_1\; e^{-2\Gamma_1^2}L_N(4\Gamma_1^2))^2}\\\nonumber
&E^{3/4}_N=\epsilon_N\mp
\sqrt{(2\hbar\frac{\Gamma_1\Gamma_2}{\omega_0^2})^2+(\epislon_2\; e^{-2\Gamma_2^2}L_N(4\Gamma_2^2)+\epislon_1\; \sqrt{(2\hbar\frac{\Gamma_1\Gamma_2}{\omega_0^2})^2+(\epsilon_2\; e^{-2\Gamma_2^2}L_N(4\Gamma_2^2)+\epsilon_1\; e^{-2\Gamma_1^2}L_N(4\Gamma_1^2))^2}\\
\end{align}
\end{equation}