Stefano Maffezzoli Felis edited Energies.tex  over 8 years ago

Commit id: 0394c3824b14d8dfe37532e852c8ae337b622417

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\begin{equation}  ==e^{-2\alpha_{stnm}^2}(2\alpha_{stnm})^{(M-N)}\sqrt{\frac{N!}{M!}}L^{(M-N)}_N(4\alpha_{stnm}^2)\;\;\;\;\;(M\geq N)  \end{equation}  where $\alpha_{stnm}=\omega_0(\gamma_{st}-\gamma_{nm})$. Therefore, one can easily see that for $s=n$ and $t=m$ the matrix element becomes $=\delta_{MN}$ (since $D(0)=\mathbb{I}$). \id