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John Johnson edited The Moon.tex
over 10 years ago
Commit id: 6c9eb6767a852d947b96f17b81e06f63bc495fcb
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A nice rule of thumb is that the human thumb held at arm's length subtends about 1~degree. The moon is half as wide as my thumb, so we'll use $\theta_m \approx 0.5$~degrees. Using the skinny angle rule, $R_m = \theta_m a_m$. There are $2 \pi$ radians for every 360 degrees, so $0.5~{\rm degrees} = 8.3\times10^{-3}$~radians.
\begin{equation}
R_m = 3.2\times
10^8$~cm 10^8~{\rm cm}
\end{equation}
Did you catch that mistake of mine? The angular size of the Moon corresponds to its {\it diameter}, not it's radius. Thus
\begin{equation}
R_m = 1.6\times
10^8$~cm 10^8~{\rm cm}
\end{equation}
A more precise estimate is $1.7374\times10^8$~cm.