John Johnson edited The Moon.tex  over 10 years ago

Commit id: 4fef0792fa18c96ee239ed6e99da8f89157c9858

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R_m = 3.2\times 10^8~{\rm cm}  \end{equation}  Did you catch that mistake of mine? The angular size of the Moon corresponds to its {\it diameter}, not it's radius. Thus $D_m = 2 R_m = \theta_m a_m$, and  \begin{equation}  R_m = 1.6\times 10^8~{\rm cm}