deletions | additions       diff --git a/section_Application_to_Specific_Heat__.tex b/section_Application_to_Specific_Heat__.tex  index baa4ba1..856f793 100644  --- a/section_Application_to_Specific_Heat__.tex  +++ b/section_Application_to_Specific_Heat__.tex 
...
In our Jan 2015 heat capacity run, we used a 0.40 mg sample of $\kappa$-(BEDT-TTF)$_2$Cu(NCS)$_2$. In our July 2015 run, we used a 0.50 mg sample. Assuming a molar mass $m$ of $832.98 \mathrm{g/mole}$ and 1 Cu atom per mole, the nuclear contribution of the Cu nuclei to the measured heat capacity of $\kappa$-(BEDT-TTF)$_2$Cu(NCS)$_2$ is predicted to be  \begin{equation}  \label{eq:NuclearCuContribution}  c = {\alpha}_{Cu} {\alpha}  \frac{H^2}{T^2} \mathrm{\ [J/K]} \end{equation}  where $\alpha = m \frac{{\lambda}_N}{{\mu}_0}$ has units $\left[\frac{\textrm{J K}}{{\textrm{T}}^2}\right]$ and values $\alpha_{\textrm{0.4 mg}} $\alpha_{Cu}  = 1.28 \cdot 10^{-9}$ and $\alpha_{\textrm{0.5 mg}} $\alpha_{Cu}  = 1.60 \cdot 10^{-9}$ for the Jan 2015 and July 2015 runs, respectively.