Nathanael A. Fortune edited section_Application_to_Specific_Heat__.tex  over 8 years ago

Commit id: c990ef69a63cb8c5517400e52fa03830aecbd89e

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\label{eq:NuclearCuContribution}  c \mathrm{\ [J/K]} = \alpha \left(\frac{H}{T}\right)^2  \end{equation}  where $\alpha = $ 1.6035 \cdot 10^{-9}$