Nathanael A. Fortune edited section_Application_to_Specific_Heat__.tex  over 8 years ago

Commit id: a6bfd1962b32f4dd8ac2ba3898a06933f65b8f75

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where  \begin{equation}  \label{eq:NuclearHeatCapacity}  \alpha = m_{mole} \left( \frac{ {\lambda}_{Cu} + {\lambda}_{H} }{ {{\mu}_0} } \right) \right).  \end{equation}  where For the Jan 2015 run,  $\alpha_{Cu} = 4.94 \cdot 10^{-9} \left[\frac{\textrm{J K}}{{\textrm{T}}^2}\right]$ and K}}{{\textrm{T}}^2}\right]$. For the July 2015 run,  $\alpha_{Cu} = 6.18 \cdot 10^{-9} \left[\frac{\textrm{J K}}{{\textrm{T}}^2}\right]$ for the Jan 2015 and July 2015 runs, respectively. K}}{{\textrm{T}}^2}\right]$.