deletions | additions       diff --git a/section_Application_to_Specific_Heat__.tex b/section_Application_to_Specific_Heat__.tex  index f37fa7b..e73fed4 100644  --- a/section_Application_to_Specific_Heat__.tex  +++ b/section_Application_to_Specific_Heat__.tex 
...
In our Jan 2015 heat capacity run, we used a 0.40 mg sample of $\kappa$-(BEDT-TTF)$_2$Cu(NCS)$_2$. In our July 2015 run, we used a 0.50 mg sample. Assuming 1 Cu atom per mole, the nuclear contribution of the Cu nuclei to the measured heat capacity of $\kappa$-(BEDT-TTF)$_2$Cu(NCS)$_2$ is predicted to be  \begin{equation}  \label{eq:NuclearCuContribution}  c =\frac{m_{mole}}{{\mu}_0}} \left({\lamda}_{Cu} \left({\lambda}_{Cu}  + {\lamda}_{H}\right) {\lambda}_{H}\right)  \frac{H^2}{T^2} = {\alpha}+ {\alpha}  \frac{H^2}{T^2} \mathrm{\ [J/K]} \end{equation}  where$\alpha = m_{mole} \frac{{\lambda}_N}{{\mu}_0}$ and values  $\alpha_{Cu} = 1.28 \cdot 10^{-9} \left[\frac{\textrm{J K}}{{\textrm{T}}^2}\right]$ and $\alpha_{Cu} = 1.60 \cdot 10^{-9} \left[\frac{\textrm{J K}}{{\textrm{T}}^2}\right]$ for the Jan 2015 and July 2015 runs, respectively.